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0.00001x^2+0.06x-2.5=0
a = 0.00001; b = 0.06; c = -2.5;
Δ = b2-4ac
Δ = 0.062-4·0.00001·(-2.5)
Δ = 0.0037
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{0.0037}}{2*0.00001}=\frac{-0.06-\sqrt{0.0037}}{0.43656365691809} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{0.0037}}{2*0.00001}=\frac{-0.06+\sqrt{0.0037}}{0.43656365691809} $
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